Telescope FOV Calculator

Exact field of view from your camera sensor and focal length, framed to scale against the Moon and deep-sky objects.

Imaging setup

Blank or 1 for none, 2 for a 2× Barlow, 0.8 for a 0.8× reducer.

Field of view

Width × height

Framing preview

Formula and substitution

FOV = 2 × arctan(d ÷ (2 × f))

    Every number you enter stays in this browser — nothing is uploaded.

    FAQ

    Why not just use sensor ÷ focal × 57.3?

    That rule of thumb is the small-angle limit of the exact formula, 2 × arctan(dimension ÷ (2 × focal length)). Below about a 10° field they agree, but on wide lenses they part ways fast: a full-frame sensor on a 20 mm lens covers 84.0°, not the 103.1° the rule prints. This calculator always uses the exact formula and shows the rule-of-thumb value only as a comparison in the derivation.

    How do I find my camera’s sensor size?

    The preset list covers the common formats — full frame, APS-C, Micro Four Thirds, 1-inch and 44 × 33 medium format. For anything else, the camera’s specification sheet lists the sensor dimensions in millimetres; enter those directly. Dedicated astronomy cameras quote them the same way — a square 1-inch-class sensor, for example, measures about 11.3 × 11.3 mm.

    How do Barlow lenses and reducers change the field?

    They scale the effective focal length, and the field scales inversely with it. A 2× Barlow doubles the focal length and halves the field of view; a 0.8× reducer shortens the focal length to 0.8× and widens the field by 1.25×.

    Does aperture change the field of view?

    No. Aperture controls how much light reaches the sensor — exposure time and how faint a star you can record — but framing depends only on the sensor dimensions and the focal length. Two telescopes with the same focal length frame exactly the same patch of sky regardless of their aperture.

    The Mathematics of Field of View

    Calculating how much of the night sky fits onto a camera sensor requires precise geometric formulas. The Telescope FOV Calculator uses exact pinhole-camera trigonometric geometry to determine the angular coverage of an imaging system. The fundamental formula used to calculate the field of view for any given sensor dimension is:

    Width, Height, or Diagonal = 2 × arctan(d ÷ (2 × f))

    In this formula, d represents the physical dimension of the sensor in millimetres (width, height, or diagonal), and f represents the effective focal length of the optical system in millimetres.

    Many astrophotographers rely on a simplified rule of thumb known as the small-angle approximation:

    Small-angle rule: d ÷ f × 57.3

    While this approximation is highly accurate for narrow fields of view, it diverges significantly when using wide-angle lenses. For example, a full-frame sensor (36 mm width) paired with a 20 mm wide-angle lens yields an actual field of view of 84.0° using the exact trigonometric formula. The small-angle approximation incorrectly calculates this as 103.1°, introducing a substantial error. The calculator computes the exact trigonometric value for all inputs and displays the small-angle approximation side-by-side in the "Formula and substitution" section to demonstrate where the two methods diverge.


    Sensor Formats in Astrophotography

    The physical size of a camera sensor is a primary variable in determining your field of view. The calculator includes several standard sensor format presets to simplify configuration:

    • Full frame (36 × 24 mm): A standard benchmark for wide-field imaging.
    • APS-C (23.5 × 15.6 mm): Common in many DSLR and dedicated astronomy cameras.
    • APS-C Canon (22.3 × 14.9 mm): A slightly smaller APS-C variant specific to Canon sensors.
    • Micro Four Thirds (17.3 × 13 mm): Widely used in mirrorless and cooled astronomy cameras.
    • 1-inch (13.2 × 8.8 mm): Popular in compact planetary and guide cameras.
    • Medium format 44 × 33 (43.8 × 32.9 mm): Used for ultra-wide-field astrophotography.
    • Custom size: Allows manual entry of any sensor width and height in millimetres.

    Dedicated astronomy cameras often feature square or non-standard aspect ratios, such as a square 1-inch-class sensor measuring approximately 11.3 × 11.3 mm. Users can input these dimensions directly by selecting "Custom size" or editing the width and height fields, which automatically switches the preset selection to custom.


    How Focal Length and Optical Accessories Affect Framing

    Focal length is the optical property of a telescope or lens that determines its magnification and, consequently, its field of view. A longer focal length narrows the field of view, while a shorter focal length widens it.

    Astrophotographers frequently modify their system's native focal length using auxiliary optics:

    • Barlow Lenses: These increase the focal length of the system. For example, a 2× Barlow doubles the focal length, which halves the field of view.
    • Focal Reducers: These decrease the focal length. For example, a 0.8× reducer shortens the focal length to 80% of its native value, widening the field of view by 1.25×.

    The calculator accounts for these accessories through the "Barlow / reducer factor" input. The tool computes the "Effective focal length" by multiplying the native focal length by this factor. The allowed range for this factor is strictly between 0.05 and 20.


    Aperture vs. Focal Length

    A common misconception in astrophotography is that a telescope's aperture influences the field of view. It does not.

    Aperture defines the diameter of the telescope's primary mirror or lens, which dictates its light-gathering power and resolving limit. A larger aperture allows you to capture fainter details and reduces required exposure times, but it has no bearing on how a target is framed on the sensor. Framing is governed entirely by the combination of the sensor's physical dimensions and the effective focal length of the telescope. Two telescopes with vastly different apertures—such as a 70 mm refractor and a 200 mm reflector—will produce the exact same framing of a celestial target if both systems share the same focal length and camera sensor.


    Understanding Angular Sizes of Celestial Targets

    To help visualize how a target fits within your camera frame, the calculator provides a "Framing preview" that overlays your calculated field of view against various celestial objects. These targets vary widely in angular size:

    Target Type Description of Scale
    Moon / Sun Solar System Apparent size varies between approximately 30′ and 34′ (0.5° to 0.57°) depending on orbital distance.
    Jupiter Planet Extremely small angular size, requiring long focal lengths and Barlow lenses to resolve details.
    Ring Nebula (M57) / Hercules Cluster (M13) Deep-Sky Compact deep-sky targets that benefit from moderate to long focal lengths.
    Orion Nebula (M42) / Andromeda Galaxy (M31) Deep-Sky Large, bright targets that require wider fields of view to frame completely.
    North America Nebula (NGC 7000) Deep-Sky An immense emission nebula requiring short focal lengths or wide-field camera lenses to capture in full.

    The preview calculates the coverage percentage, showing how much of the frame width and height the selected object spans.


    Pinhole Camera Geometry and Lens Distortion

    The calculations performed by this tool assume perfect pinhole-camera geometry. In an idealized optical system, light rays pass straight through the optical center to the flat sensor plane.

    In the real world, physical lenses introduce optical distortion, particularly at very wide focal lengths. Ultra-wide-angle and fisheye lenses do not project light in a perfectly linear fashion. As a result, the corners of wide-field images will stretch further in reality than the idealized geometric boundaries shown in the preview. Additionally, the preview uses typical angular extents for celestial objects. Because the distances of the Moon and Sun from Earth fluctuate, their actual angular sizes vary slightly over time. The preview serves as a scale sketch for planning purposes rather than a real-time star chart.


    Local Processing and Privacy

    Every calculation is performed locally within your web browser. No data, sensor dimensions, or optical specifications are uploaded to external servers. The tool operates entirely on your local device, ensuring your inputs remain private.


    Frequently Asked Questions

    Why not just use sensor ÷ focal × 57.3? That rule of thumb is the small-angle limit of the exact formula, 2 × arctan(dimension ÷ (2 × focal length)). Below about a 10° field they agree, but on wide lenses they part ways fast: a full-frame sensor on a 20 mm lens covers 84.0°, not the 103.1° the rule prints. This calculator always uses the exact formula and shows the rule-of-thumb value only as a comparison in the derivation.

    How do I find my camera’s sensor size? The preset list covers the common formats — full frame, APS-C, Micro Four Thirds, 1-inch and 44 × 33 medium format. For anything else, the camera’s specification sheet lists the sensor dimensions in millimetres; enter those directly. Dedicated astronomy cameras quote them the same way — a square 1-inch-class sensor, for example, measures about 11.3 × 11.3 mm.

    How do Barlow lenses and reducers change the field? They scale the effective focal length, and the field scales inversely with it. A 2× Barlow doubles the focal length and halves the field of view; a 0.8× reducer shortens the focal length to 0.8× and widens the field by 1.25×.

    Does aperture change the field of view? No. Aperture controls how much light reaches the sensor — exposure time and how faint a star you can record — but framing depends only on the sensor dimensions and the focal length. Two telescopes with the same focal length frame exactly the same patch of sky regardless of their aperture.